Posted by A Veteran on September 30, 2007, 1:32 am
If you heat up a cast iron pan slowly it saves energy. try it!
--
when you believe the only tool you have is a hammer.
All problems look like nails.
Posted by Logan Shaw on September 30, 2007, 3:26 am
A Veteran wrote:
> If you heat up a cast iron pan slowly it saves energy. try it!
Seems counter-intuitive. The more time you spend heating it up, the
longer time period over which it is losing heat to the environment.
Heat loss is basically the integral of temperature difference over
time (because the rate of heat transfer is essentially proportional
to temperature difference). Of course there are lots of complicating
factors like air currents and convection, but in the absence of
evidence to the contrary, I'd put my money on heating it as fast as
possible being the most energy-efficient thing.
- Logan
Posted by nicksanspam on September 30, 2007, 1:42 pm
>Heat loss is basically the integral of temperature difference over
>time (because the rate of heat transfer is essentially proportional
>to temperature difference). Of course there are lots of complicating
>factors like air currents and convection, but in the absence of
>evidence to the contrary, I'd put my money on heating it as fast as
>possible being the most energy-efficient thing.
With radiation loss increasing with T^4, it might pay to keep
an electric stove burner cooler.
Nick
Posted by Logan Shaw on September 30, 2007, 4:50 pm
nicksanspam@ece.villanova.edu wrote:
>
>> Heat loss is basically the integral of temperature difference over
>> time (because the rate of heat transfer is essentially proportional
>> to temperature difference). Of course there are lots of complicating
>> factors like air currents and convection, but in the absence of
>> evidence to the contrary, I'd put my money on heating it as fast as
>> possible being the most energy-efficient thing.
> With radiation loss increasing with T^4, it might pay to keep
> an electric stove burner cooler.
Interesting point. My gut feeling is that the reflector ("drip pan")
will make up for a lot of that and a lot of the radiated heat will end
up in the cookware anyway (plus the temperature difference between the
burner and the cookware might not be that large because the "contact
patch" between them is big). But on the other hand, T^4 is a REALLY
fast-growing function...
- Logan
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